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unsigned int造句

例句與造句

  1. Likewise, arguments of types narrower than an int will be promoted to int or unsigned int.
  2. In many aspects, it behaves much like an unsigned int, but conversions from other integer types or pointers always constrained to 0 and 1.
  3. In C and C + +, native implementation-defined bit fields can be created using unsigned int, signed int, or ( in C99 : ) _ Bool.
  4. A struct is just a short-cut in C language to allocate many bytes and tell the compiler how each byte should be interpreted ( e . g . first few as an unsigned int, next few bytes as a pointer, etc ).
  5. When you cast one of those to unsigned int, you don't get an unsigned int ranging from 0 to 255 but one ranging from 0 to 127 or UINT _ MAX-127 to UINT _ MAX . You should declare in _ char and out _ char as unsigned.
  6. It's difficult to find unsigned int in a sentence. 用unsigned int造句挺難的
  7. When you cast one of those to unsigned int, you don't get an unsigned int ranging from 0 to 255 but one ranging from 0 to 127 or UINT _ MAX-127 to UINT _ MAX . You should declare in _ char and out _ char as unsigned.
  8. In addition to the assumption about bit-representation of floating-point numbers, the previous floating-point type-punning example also violates the C language's constraints on how objects are accessed : the declared type of x is float but it is read through an expression of type unsigned int.
  9. The casts to unsigned int are not doing you any good at all, and if you hadn't used them you might have got some warnings from your compiler about using a possibly-signed char as an array subscript . ( Or maybe you already saw that warning and decided to cover it up by casting . . . which is usually not the right thing to do ).
  10. Note, however, that the implementation of addSwap above in the C programming language always works even in case of integer overflow, since, according to the C standard, addition and subtraction of unsigned integers follow the rules of modular arithmetic, i . e . are done in the cyclic group \ mathbb Z / 2 ^ s \ mathbb Z where s is the number of bits of unsigned int.
  11. In C's stdlib . h, why do abs ( ) and labs ( ) return a signed integer type, given that returning an unsigned type would eliminate the anomaly involving abs ( INT _ MIN ) and labs ( LONG _ MIN ) ( and would make it safe to write ( long ) abs ( x ) instead of ( long ) ( unsigned int ) abs ( x ) )?

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