unsigned int造句
例句與造句
- Likewise, arguments of types narrower than an int will be promoted to int or unsigned int.
- In many aspects, it behaves much like an unsigned int, but conversions from other integer types or pointers always constrained to 0 and 1.
- In C and C + +, native implementation-defined bit fields can be created using unsigned int, signed int, or ( in C99 : ) _ Bool.
- A struct is just a short-cut in C language to allocate many bytes and tell the compiler how each byte should be interpreted ( e . g . first few as an unsigned int, next few bytes as a pointer, etc ).
- When you cast one of those to unsigned int, you don't get an unsigned int ranging from 0 to 255 but one ranging from 0 to 127 or UINT _ MAX-127 to UINT _ MAX . You should declare in _ char and out _ char as unsigned.
- It's difficult to find unsigned int in a sentence. 用unsigned int造句挺難的
- When you cast one of those to unsigned int, you don't get an unsigned int ranging from 0 to 255 but one ranging from 0 to 127 or UINT _ MAX-127 to UINT _ MAX . You should declare in _ char and out _ char as unsigned.
- In addition to the assumption about bit-representation of floating-point numbers, the previous floating-point type-punning example also violates the C language's constraints on how objects are accessed : the declared type of x is float but it is read through an expression of type unsigned int.
- The casts to unsigned int are not doing you any good at all, and if you hadn't used them you might have got some warnings from your compiler about using a possibly-signed char as an array subscript . ( Or maybe you already saw that warning and decided to cover it up by casting . . . which is usually not the right thing to do ).
- Note, however, that the implementation of addSwap above in the C programming language always works even in case of integer overflow, since, according to the C standard, addition and subtraction of unsigned integers follow the rules of modular arithmetic, i . e . are done in the cyclic group \ mathbb Z / 2 ^ s \ mathbb Z where s is the number of bits of unsigned int.
- In C's stdlib . h, why do abs ( ) and labs ( ) return a signed integer type, given that returning an unsigned type would eliminate the anomaly involving abs ( INT _ MIN ) and labs ( LONG _ MIN ) ( and would make it safe to write ( long ) abs ( x ) instead of ( long ) ( unsigned int ) abs ( x ) )?